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4x^2-60x+176=0
a = 4; b = -60; c = +176;
Δ = b2-4ac
Δ = -602-4·4·176
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-28}{2*4}=\frac{32}{8} =4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+28}{2*4}=\frac{88}{8} =11 $
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